133. Clone Graph
DFS, BFS, Graph, Hash Table, Review ·Problem Statement
link: https://leetcode.com/problems/clone-graph/submissions/ https://leetcode.cn/problems/clone-graph/submissions/
Given a reference of a node in a connected undirected graph.
Return a deep copy (clone) of the graph.
Each node in the graph contains a value (int) and a list (List[Node]) of its neighbors.
class Node {
public int val;
public List
Test case format:
For simplicity, each node’s value is the same as the node’s index (1-indexed). For example, the first node with val == 1, the second node with val == 2, and so on. The graph is represented in the test case using an adjacency list.
An adjacency list is a collection of unordered lists used to represent a finite graph. Each list describes the set of neighbors of a node in the graph.
The given node will always be the first node with val = 1. You must return the copy of the given node as a reference to the cloned graph.
Example:
Input: adjList = [[2,4],[1,3],[2,4],[1,3]]
Output: [[2,4],[1,3],[2,4],[1,3]]
Input: adjList = [[]]
Output: [[]]
Input: adjList = []
Output: [[]]
Solution Approach
The solution is based on depth-first traversal where each node’s clone is created recursively ensuring no duplicate clones.
Algorithm
- Initialize a dictionary to store visited nodes to avoid cyclic cloning and store clones associated with the original node.
- Start the depth-first traversal from the given node. If the node is already visited, return the cloned node from the visited dictionary.
- If not visited, create a new clone of the current node, add it to the visited dictionary, and recursively clone all its neighbors. Finally, return the cloned node.
Implement
class Solution:
def __init__(self):
self.visit = {}
def cloneGraph(self, node: Optional['Node']) -> Optional['Node']:
if not node:
return node
if node in self.visit:
return self.visit[node]
res = Node(node.val, [])
self.visit[node] = res
if node.neighbors:
res.neighbors = [self.cloneGraph(n) for n in node.neighbors]
return res